Some fire pump assemblies have closed-test loops. When we circulate water through this closed test loop, why does the suction pressure not increase?
I'd be interested in understanding the physics of the situation a little better here. Posted anonymously for discussion. Discuss This | Submit Your Question | Subscribe
8 Comments
Franck
12/16/2020 10:01:54 am
I hope that the water from the test line is delivered at the top of the tank and not on your pump suction side !
Reply
Franck
12/16/2020 10:23:57 am
Which means that with this installation, you are not increasing the pressure on the suction side (the water being delivered at the top of the tank has no pressure adding effect inside the tank).
Reply
Colin Lusher
12/17/2020 01:39:10 pm
Frank, the closed test header loop as shown in NFPA 20 Figure A4.22.1.3(b) (2019) version is what the OP is talking about. This closed loop flows from the pump discharge directly back to the pump suction. We see these quite a bit in the US as we don't often use tanks for buildings that aren't high rises....we pull suction water from the public water supply.
Alex L
12/16/2020 02:13:32 pm
Apologies in advance for the long reply... If I understand the question correctly, the OP is asking about an arrangement that is very common in the United States- a “closed test loop” which is a piping loop with a flow meter from the discharge side of the fire pump to the suction side. The simplest answer is equilibrium. Bernoulli's principle for fluid dynamics states that an increase in the speed of a fluid occurs simultaneously with a decrease in static pressure or a decrease in the fluid's potential energy. If that is not enough for you, we can break down some of the reasons why that is the case. A closed test loop is a fixed “system” with conservation of mass (there is no mass entering or leaving the system; i.e. the total mass of water is constant in the loop). With a check valve preventing more water from entering upstream of the pump, and no outlets in the fire protection system downstream of the loop, the water that we are boosting with the pump is the same water we are pulling from. Think of the system as two points, one on the discharge side (1) and one on the suction side (2), which are separated by the loop piping. There are two physical interpretations of the Bernoulli equation, one where energy is conserved (total head of the flowing fluid is constant along a streamline), and the other where pressure head and velocity head vary inversely. There are three terms in the Bernoulli equation, all related to head (if you remember, head is the concept that balances work and energy in a flowing fluid): Velocity head characterizes kinetic energy of the flowing fluid, elevation head is the gravitational potential energy of the fluid, and pressure head is the work done by the pressure force. Since the elevation of the two points (discharge side and suction side of the pump) does not change, we are left with pressure and velocity head. We control the flow through the flow meter by throttling the valve downstream of the flow meter, which allows more water to flow through the loop. Since the pipe diameter is constant, and flow is equal to velocity over an area (ft/s * ft^2 = volume/time), as we increase the flow rate we are increasing the velocity, which increases the velocity head term of the equation. This necessitates that the pressure head term must decrease. Remember that the combined head at (1) and (2) MUST be the same (in other words, the total energy of the loop must remain the same). One reason this occurs is friction! Remember that the Darcy-Weisbach equation for friction loss has several components: length of pipe, diameter of pipe, friction coefficient, acceleration due to gravity and velocity. The amount of friction loss will vary with velocity. TL;DR version: Another way to rephrase, when we flow more, velocity increases which results in more friction loss, keeping suction pressure constant in the loop. I hope that helps. (Source: my brain and applying concepts taken from the textbook Engineering Fluid Mechanics, 10th Edition)
Reply
Franck
12/17/2020 08:51:29 am
Many thanks for this extensive technical reply :)
Reply
CESAR AUGUSTO VILLAVICENCIO
9/8/2024 08:29:30 am
Dear Sirs,
Reply
ztsvi
12/18/2020 02:37:20 pm
This type of setup uses a loop of pipe which feeds back into pump suction. This means that in terms of energy, you effectively have the same elevation and mass flow rate throughout the loop. The energy input by the pump is in the form of pressure and heat.
Reply
Franck
12/23/2020 10:24:07 am
Many thanks for the explanations
Reply
Leave a Reply. |
ALL-ACCESSSUBSCRIBESubscribe and learn something new each day:
COMMUNITYTop November '24 Contributors
YOUR POSTPE EXAMGet 100 Days of Free Sample Questions right to you!
FILTERS
All
ARCHIVES
December 2024
PE PREP SERIES |