Daily Discussion (today's anonymously submitted question): Reviewing the Example 2 on SFPE (4th) page 4-307, could not understand how it is W/D = 0.67 lb/ft-in. Here is the effort:
D: As per figure 4-11.10 on page 4-305 D = 2(a + b) So, Added 2.5 inches to beam flange, a becomes 9.035, and b becomes 10.56 D = 2(9.035 + 10.56) D = 2(19.595) D = 39.19 W/D = 94.55 ÷ 39.19 = 2.413 What is not right? Note: This is a Daily Discussion question submitted anonymously to us. Submit Your Own Question or Discuss This Here.
7 Comments
CJ
9/15/2017 09:46:20 am
W is 28 lb/ft (the second number in 'W8x28').
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a
9/15/2017 10:25:56 am
Why hire a competent editor when you can crowd source it.(Busch league)
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Jay
9/15/2017 11:03:46 am
Unwelcomed controversy.
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CJ
9/15/2017 11:17:59 am
Just to be clear, it's only the SFPE materials (Handbook and Reference Manual) which I think are poorly written.
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Joe Meyer
9/15/2017 11:30:39 am
Thanks CJ! That being said I have looked into getting editing support for the 2018 edition of the Prep Guide.
Reply
a
9/15/2017 11:33:27 am
I was referring to the SFPE review manual/handbook not your guide Joe.
Reply
Joe Meyer
9/15/2017 12:49:19 pm
I try my best but no doubt it's difficult to get it all correct - I do see now that I misread your earlier post, but I appreciate the followup!
Reply
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