PE Problem #58

8/23/2018

A 52 ft long by 22 ft wide by 10 ft tall space contains high value historic newspapers in pervious metal storage. If the space is to be kept at 72 deg F and has fixed structures of 194 cubic feet, what minimum quantity of FM-200 agent would be required to protect the space in a full flood application if the design concentration is 6.7%?
a. 340 lb
b. 364 lb
c. 437 lb
d. Other

Solution | Posted 08/24/18

7 Comments

8/23/2018 09:23:18 am

Answer: d
Source: Problem 53 on page 177 of 2018 MeyerFire PE Prep Guide. When I run the information in the equation I get approximately 443 lbs.

8/23/2018 09:42:04 am

B
NFPA HB - p. 17-113, Eqn (1) and (2)

Jimmy

8/23/2018 09:49:15 am

B. I confess that my calculator batteries died so I used my phone. (I'm an old RPN guy, so the odds of an error go way up with an equals key involved!) Keep that in mind, folks: have a backup calculator during the exam. It would suck doing that many problems by hand.

Colleen

8/23/2018 09:50:37 am

I got B. 364 lb

per FPH 17-113 and 114,
weight required=V/S*(C/(100-C))
V=[52*22*10]-194=11,246
S=k1+k2*T. Using values of k for FM-200 and T of 72, get
S=1.879775+0.0046625*(72)=2.215
C, design concentration given in problem=6.7, plugging in values, I got a weight of 364 pounds of FM-200

8/23/2018 10:14:15 am

B
I didn't have my Handbooks nore Meyer with me, so I used the fine print under table A.5.5.1(i) in 2001.

David

8/23/2018 11:04:30 am

Pari

8/23/2018 11:33:34 am

B , I follow the example problem # 53 from Meyer fire book

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