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Working on the fire protection for a new industrial building. I only have two small areas to protect with sprinklers:
1. 400 ft² hydraulic room 2. 520 ft² transformer room Both are considered Extra Hazard due to the presence of flammable liquids. My understanding of NFPA 13 forces me to use 2500 ft² and 0.50 gpm/ft² as the minimum water supply. This will give me 1250 gpm of water to apply to very small rooms, which doesn't make much sense to me. Am I understanding this right? Is there a way around it, or a different way of calculating the water supply need? Thanks in advance. Sent in anonymously for discussion. Click Title to View | Submit Your Question | Subscribe
10 Comments
Pete H
3/5/2026 06:18:56 am
From NFPA 13 (2025 edition)
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Quentin F
3/6/2026 01:27:53 am
Our insurance asked for a 0.5gpm/ft2 density.
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Dan Wilder
3/5/2026 07:12:42 am
Ya, there's a bit more to this for information needed.
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Glenn Berger
3/5/2026 08:09:54 am
You have some very good answers so far.
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Chad
3/5/2026 09:21:17 am
Glenn is on to something here, kinda odd.
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Quentin F
3/6/2026 01:34:18 am
The rest of the site is protected mostly with fire hydrants.
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Anthony
3/5/2026 09:38:18 am
I agree with others that the rooms could be designed independent of other areas. Phantom flow can be descoped with an e-mail to the AHJ often.
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Dustin T
3/5/2026 09:54:47 am
I too question why you have only two rooms in a new industrial building.
Reply
Jack G
3/5/2026 04:21:33 pm
The way it’s stated in NFPA 13 , phantom flow is only for density area method calculations say an ordinary hazard calculation with a small room that may be extra hazard.
Reply
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